What is ((y^{-2})/(3x^{-3)})^4 ?

The solution to ((y^{-2})/(3x^{-3)})^4 is (x^{12})/(81y^8)

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simplify ((y^{-2})/(3x^{-3)})^4

simplify

(\frac{y ^{- 2}}{3 x ^{- 3}})^{4}

\frac{x ^{12}}{81 y ^{8}}

Solution steps

(\frac{y ^{- 2}}{3 x ^{- 3}})^{4}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( y ^{- 2} ) ^{4}}{( 3 x ^{- 3} ) ^{4}}

Simplify

(y^{- 2})^{4} : \frac{1}{y ^{8}}

= \frac{\frac{1}{y ^{8}}}{( 3 x ^{- 3} ) ^{4}}

Simplify

(3 x^{- 3})^{4} : \frac{81}{x ^{12}}

= \frac{\frac{1}{y ^{8}}}{\frac{81}{x ^{12}}}

Simplify

\frac{\frac{1}{y ^{8}}}{\frac{81}{x ^{12}}} : \frac{x ^{12}}{81 y ^{8}}

= \frac{x ^{12}}{81 y ^{8}}

\frac{3}{4} x^{8}

\frac{3}{4} x^{3}

\frac{5}{6} + \frac{8}{9}

\frac{x ^{3} - x}{x ^{2} - 1}

(3 + 15)^{2}

What is ((y^{-2})/(3x^{-3)})^4 ?
The solution to ((y^{-2})/(3x^{-3)})^4 is (x^{12})/(81y^8)