What is (3k)/(3k-6)-(2k)/(k+3) ?

The solution to (3k)/(3k-6)-(2k)/(k+3) is (-k^2+7k)/((k-2)(k+3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (3k)/(3k-6)-(2k)/(k+3)

simplify

\frac{3 k}{3 k - 6} - \frac{2 k}{k + 3}

\frac{- k ^{2} + 7 k}{( k - 2 ) ( k + 3 )}

Solution steps

\frac{3 k}{3 k - 6} - \frac{2 k}{k + 3}

Cancel

\frac{3 k}{3 k - 6} : \frac{k}{k - 2}

= \frac{k}{k - 2} - \frac{2 k}{k + 3}

Simplify

\frac{k}{k - 2} - \frac{2 k}{k + 3} : \frac{k ( k + 3 ) - 2 k ( k - 2 )}{( k - 2 ) ( k + 3 )}

= \frac{k ( k + 3 ) - 2 k ( k - 2 )}{( k - 2 ) ( k + 3 )}

Simplify

k (k + 3) - 2 k (k - 2) : - k^{2} + 7 k

= \frac{- k ^{2} + 7 k}{( k - 2 ) ( k + 3 )}

\frac{0. 9 ^{4} - 1}{0. 9 ^{6} - 1}

a^{- x}

a x (x + 1)

(- 5) (- 9)

(- 5) (- 8)

What is (3k)/(3k-6)-(2k)/(k+3) ?
The solution to (3k)/(3k-6)-(2k)/(k+3) is (-k^2+7k)/((k-2)(k+3))