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Popular >

4|x-9|-1<= 15

Solution

4 ∣ x - 9 ∣ - 1 \leq 15

Solution

5 \leq x \leq 13

+1

Interval Notation

[5, 13]

Solution steps

4 ∣ x - 9 ∣ - 1 \leq 15

Move

1

to the right side

4 ∣ x - 9 ∣ \leq 16

Divide both sides by

4

∣ x - 9 ∣ \leq 4

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 4 \leq x - 9 \leq 4

x - 9 \geq - 4 and x - 9 \leq 4

x \geq 5 and x \leq 13

Merge Overlapping Intervals

5 \leq x \leq 13

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3 i

∣ 4 x + 8 ∣ + 19 = 6

1 x^{2} + 3 x - 28 = 0

factor y^2-x^2+2x-1 factor

y^{2} - x^{2} + 2 x - 1

simplify (7/8)^{1.8}simplify

(\frac{7}{8})^{1.8}

Frequently Asked Questions (FAQ)

What is 4|x-9|-1<= 15 ?
The solution to 4|x-9|-1<= 15 is 5<= x<= 13