What are the solutions to the equation m^2=1m ?

The solutions to the equation m^2=1m are m=1,m=0

Find the zeros of m^2=1m

The zeros of m^2=1m are m=1,m=0

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m^{2} = 1 m

m = 1, m = 0

Solution steps

m^{2} = 1 \cdot m

Refine

m^{2} = m

Move

m

to the left side

m^{2} - m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

m_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, m_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

m = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

m = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

m = 1, m = 0

4 x < 16

5 x^{2} + 13 x + 6 = 0

\frac{a}{8} < 3

30 = ∣ v - 30 ∣

- 16 \geq - 2 y

What are the solutions to the equation m^2=1m ?
The solutions to the equation m^2=1m are m=1,m=0
Find the zeros of m^2=1m
The zeros of m^2=1m are m=1,m=0