What is factor 2j^{17}+32j^{482} ?

The solution to factor 2j^{17}+32j^{482} is 2j^{17}(16j^{465}+1)

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factor 2j^{17}+32j^{482}

factor

2 j^{17} + 32 j^{482}

2 j^{17} (16 j^{465} + 1)

Solution steps

2 j^{17} + 32 j^{482}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

j^{482} = j^{465} j^{17}

= 32 j^{465} j^{17} + 2 j^{17}

Rewrite

32

2 \cdot 16

= 2 \cdot 16 j^{465} j^{17} + 2 j^{17}

Factor out common term

2 j^{17}

= 2 j^{17} (16 j^{465} + 1)

[(x - 3 y) + z] [(x - 3 y) - z]

16 r^{2} - π r^{2}

2 b^{3} + 3 c^{3} - 2 b^{3} x - 3 c^{3} x

cos (x^{2} - 1)

10 - 221

What is factor 2j^{17}+32j^{482} ?
The solution to factor 2j^{17}+32j^{482} is 2j^{17}(16j^{465}+1)