What are the solutions to the equation 13x^2-x+6=0 ?

The solutions to the equation 13x^2-x+6=0 are x= 1/26+i(sqrt(311))/(26),x= 1/26-i(sqrt(311))/(26)

Find the zeros of 13x^2-x+6=0

The zeros of 13x^2-x+6=0 are x= 1/26+i(sqrt(311))/(26),x= 1/26-i(sqrt(311))/(26)

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13 x^{2} - x + 6 = 0

x = \frac{1}{26} + i \frac{311}{26}, x = \frac{1}{26} - i \frac{311}{26}

Solution steps

13 x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 13 \cdot 6}{2 \cdot 13}

Simplify

(- 1)^{2} - 4 \cdot 13 \cdot 6 : 311 i

x_{1, 2} = \frac{- ( - 1 ) \pm 311 i}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 311 i}{2 \cdot 13}, x_{2} = \frac{- ( - 1 ) - 311 i}{2 \cdot 13}

x = \frac{- ( - 1 ) + 311 i}{2 \cdot 13} : \frac{1}{26} + i \frac{311}{26}

x = \frac{- ( - 1 ) - 311 i}{2 \cdot 13} : \frac{1}{26} - i \frac{311}{26}

The solutions to the quadratic equation are:

x = \frac{1}{26} + i \frac{311}{26}, x = \frac{1}{26} - i \frac{311}{26}

\frac{3}{2} + \frac{3}{4}

6 \cdot 2

6 - (- 5 + 4 i) - (- 13 - i)

\frac{ln ( 2 )}{0.07}

What are the solutions to the equation 13x^2-x+6=0 ?
The solutions to the equation 13x^2-x+6=0 are x= 1/26+i(sqrt(311))/(26),x= 1/26-i(sqrt(311))/(26)
Find the zeros of 13x^2-x+6=0
The zeros of 13x^2-x+6=0 are x= 1/26+i(sqrt(311))/(26),x= 1/26-i(sqrt(311))/(26)