What are the solutions to the equation 2(x-2)^2+8(x-2)-1=0 ?

The solutions to the equation 2(x-2)^2+8(x-2)-1=0 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

Find the zeros of 2(x-2)^2+8(x-2)-1=0

The zeros of 2(x-2)^2+8(x-2)-1=0 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

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2 (x - 2)^{2} + 8 (x - 2) - 1 = 0

x = \frac{3}{2}, x = - \frac{3}{2}

Solution steps

2 (x - 2)^{2} + 8 (x - 2) - 1 = 0

Expand

2 (x - 2)^{2} + 8 (x - 2) - 1 : 2 x^{2} - 9

2 x^{2} - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

0^{2} - 4 \cdot 2 (- 9) = 62

x_{1, 2} = \frac{- 0 \pm 6 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 0 + 6 2}{2 \cdot 2}, x_{2} = \frac{- 0 - 6 2}{2 \cdot 2}

x = \frac{- 0 + 6 2}{2 \cdot 2} : \frac{3}{2}

x = \frac{- 0 - 6 2}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{3}{2}

5 x - 6 = 2 x

\frac{1 1 ^{14}}{1 1 ^{18}}

- 2 x^{2} \geq x - 1

- 3 x \geq 3

2 x^{2} - 20 x - 30 = 0

What are the solutions to the equation 2(x-2)^2+8(x-2)-1=0 ?
The solutions to the equation 2(x-2)^2+8(x-2)-1=0 are x= 3/(sqrt(2)),x=-3/(sqrt(2))
Find the zeros of 2(x-2)^2+8(x-2)-1=0
The zeros of 2(x-2)^2+8(x-2)-1=0 are x= 3/(sqrt(2)),x=-3/(sqrt(2))