What is factor 25x^{2n}-1/16 ?

The solution to factor 25x^{2n}-1/16 is (5x^n+1/4)(5x^n-1/4)

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factor 25x^{2n}-1/16

factor

25 x^{2 n} - \frac{1}{16}

(5 x^{n} + \frac{1}{4}) (5 x^{n} - \frac{1}{4})

Solution steps

25 x^{2 n} - \frac{1}{16}

Rewrite

25 x^{2 n}

(5 x^{1 n})^{2}

= (5 x^{1 \cdot n})^{2} - \frac{1}{16}

Apply radical rule:

a = (a)^{2}

\frac{1}{16} = (\frac{1}{16})^{2}

= (5 x^{1 n})^{2} - (\frac{1}{16})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(5 x^{1 n})^{2} - (\frac{1}{16})^{2} = (5 x^{1 n} + \frac{1}{16}) (5 x^{1 n} - \frac{1}{16})

= (5 x^{1 n} + \frac{1}{16}) (5 x^{1 n} - \frac{1}{16})

Refine

= (5 x^{n} + \frac{1}{4}) (5 x^{n} - \frac{1}{4})

a x + b x + a w + b w

(x^{3} + 2 x) + (3 x^{2} - 1)

(x) d x

+ (12)

m^{(3 a - 2 b)}

What is factor 25x^{2n}-1/16 ?
The solution to factor 25x^{2n}-1/16 is (5x^n+1/4)(5x^n-1/4)