What are the solutions to the equation x^2-13x+15=0 ?

The solutions to the equation x^2-13x+15=0 are x=(13+sqrt(109))/2 ,x=(13-sqrt(109))/2

Find the zeros of x^2-13x+15=0

The zeros of x^2-13x+15=0 are x=(13+sqrt(109))/2 ,x=(13-sqrt(109))/2

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x^{2} - 13 x + 15 = 0

x = \frac{13 + 109}{2}, x = \frac{13 - 109}{2}

Solution steps

x^{2} - 13 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 15 = 109

x_{1, 2} = \frac{- ( - 13 ) \pm 109}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 109}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 109}{2 \cdot 1}

x = \frac{- ( - 13 ) + 109}{2 \cdot 1} : \frac{13 + 109}{2}

x = \frac{- ( - 13 ) - 109}{2 \cdot 1} : \frac{13 - 109}{2}

The solutions to the quadratic equation are:

x = \frac{13 + 109}{2}, x = \frac{13 - 109}{2}

x^{2} - 2 x - 3 = 0

5 x^{2} = 25

- 4 x^{4} + 16 x^{3} + 128 x^{2}

0.2 \cdot 0.5

25 x^{4} - y^{2}

What are the solutions to the equation x^2-13x+15=0 ?
The solutions to the equation x^2-13x+15=0 are x=(13+sqrt(109))/2 ,x=(13-sqrt(109))/2
Find the zeros of x^2-13x+15=0
The zeros of x^2-13x+15=0 are x=(13+sqrt(109))/2 ,x=(13-sqrt(109))/2