What is factor 7x^{-5}+4x^{-3}+2x ?

The solution to factor 7x^{-5}+4x^{-3}+2x is (7+4x^2+2x^6)/(x^5)

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factor 7x^{-5}+4x^{-3}+2x

factor

7 x^{- 5} + 4 x^{- 3} + 2 x

\frac{7 + 4 x ^{2} + 2 x ^{6}}{x ^{5}}

Solution steps

7 x^{- 5} + 4 x^{- 3} + 2 x

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{- 3} = x^{- 5} x^{2}, x = x^{- 5} x^{6}

= 7 (x^{- 5} x^{6})^{- 5} + 4 x^{- 5} x^{2} + 2 x^{- 5} x^{6}

Factor out common term

x^{- 5}

= x^{- 5} (7 + 4 x^{2} + 2 x^{6})

Refine

= \frac{2 x ^{6} + 4 x ^{2} + 7}{x ^{5}}

[4.6]

(sin (x))^{4} + (cos (x))^{4}

9 - x^{2}

e^{x + h} - e^{x}

sin^{2} (x) + sin (x) - 2

What is factor 7x^{-5}+4x^{-3}+2x ?
The solution to factor 7x^{-5}+4x^{-3}+2x is (7+4x^2+2x^6)/(x^5)