What is factor (2x+1)^2-8(2x+1)+16 ?

The solution to factor (2x+1)^2-8(2x+1)+16 is (2x-3)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor (2x+1)^2-8(2x+1)+16

factor

(2 x + 1)^{2} - 8 (2 x + 1) + 16

(2 x - 3)^{2}

Solution steps

(2 x + 1)^{2} - 8 (2 x + 1) + 16

Expand

(2 x + 1)^{2} - 8 (2 x + 1) + 16 : 4 x^{2} - 12 x + 9

= 4 x^{2} - 12 x + 9

Factor

4 x^{2} - 12 x + 9 : (2 x - 3)^{2}

= (2 x - 3)^{2}

4 - x^{2}

x^{2} - 0.0001 y^{4}

- (a)^{3}

m^{9} n^{15} + p^{3}

3 a c + 2 b c - 6 a d - 4 b d

What is factor (2x+1)^2-8(2x+1)+16 ?
The solution to factor (2x+1)^2-8(2x+1)+16 is (2x-3)^2