What are the solutions to the equation (t-4)^2=7 ?

The solutions to the equation (t-4)^2=7 are t=sqrt(7)+4,t=-sqrt(7)+4

Find the zeros of (t-4)^2=7

The zeros of (t-4)^2=7 are t=sqrt(7)+4,t=-sqrt(7)+4

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(t - 4)^{2} = 7

t = 7 + 4, t = - 7 + 4

Decimal Notation

t = 6.64575 \dots, t = 1.35424 \dots

Solution steps

(t - 4)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

t - 4 = 7 : t = 7 + 4

Solve

t - 4 = - 7 : t = - 7 + 4

The solutions to the quadratic equation are:

t = 7 + 4, t = - 7 + 4

9 x > x^{2} + 14

- 16 x^{2} + 60 x + 16

\frac{( 76 + 74 + p )}{3} > 78

- x^{2} + 4 \geq 0

(7 - 2) (8 + 2)

What are the solutions to the equation (t-4)^2=7 ?
The solutions to the equation (t-4)^2=7 are t=sqrt(7)+4,t=-sqrt(7)+4
Find the zeros of (t-4)^2=7
The zeros of (t-4)^2=7 are t=sqrt(7)+4,t=-sqrt(7)+4