What is factor y^{12}-8 ?

The solution to factor y^{12}-8 is (y^4-2)(y^8+2y^4+4)

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factor y^{12}-8

factor

y^{12} - 8

(y^{4} - 2) (y^{8} + 2 y^{4} + 4)

Solution steps

y^{12} - 8

Apply exponent rules

= (y^{4})^{3} - 2^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(y^{4})^{3} - 2^{3} = (y^{4} - 2) (y^{8} + 2 y^{4} + 2^{2})

= (y^{4} - 2) (y^{8} + 2 y^{4} + 2^{2})

2^{2} = 4

= (y^{4} - 2) (y^{8} + 2 y^{4} + 4)

20 x - 5 x^{2}

k^{2} + (2 k + 1)

+ (x y - 1) (x - 1) (y + 1) - x y

e^{(x - y)}

e^{x} - e^{- x}

What is factor y^{12}-8 ?
The solution to factor y^{12}-8 is (y^4-2)(y^8+2y^4+4)