What is factor m^3n^6-64p^3 ?

The solution to factor m^3n^6-64p^3 is (mn^2-4p)(m^2n^4+4mn^2p+16p^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor m^3n^6-64p^3

factor

m^{3} n^{6} - 64 p^{3}

(m n^{2} - 4 p) (m^{2} n^{4} + 4 m n^{2} p + 16 p^{2})

Solution steps

m^{3} n^{6} - 64 p^{3}

Rewrite

m^{3} n^{6}

(m n^{2})^{3}

Rewrite

64 p^{3}

(2^{2} p)^{3}

= (m n^{2})^{3} - (2^{2} p)^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(m n^{2})^{3} - (2^{2} p)^{3} = (m n^{2} - 2^{2} p) ((m n^{2})^{2} + m n^{2} 2^{2} p + (2^{2} p)^{2})

= (m n^{2} - 2^{2} p) ((m n^{2})^{2} + m n^{2} 2^{2} p + (2^{2} p)^{2})

Simplify

(m n^{2} - 2^{2} p) ((m n^{2})^{2} + m n^{2} \cdot 2^{2} p + (2^{2} p)^{2}) : (m n^{2} - 4 p) (m^{2} n^{4} + 4 m n^{2} p + 16 p^{2})

= (m n^{2} - 4 p) (m^{2} n^{4} + 4 m n^{2} p + 16 p^{2})

[- 38.38]

x^{2} + 9 x + 20.25

b x^{2} - 2 b y + 5 x^{2} - 10 y

\frac{d}{d y} ((x (y)) (y))

t^{3} u - 3 t u + t^{2} w^{2} - 3 w^{2}

What is factor m^3n^6-64p^3 ?
The solution to factor m^3n^6-64p^3 is (mn^2-4p)(m^2n^4+4mn^2p+16p^2)