What are the solutions to the equation 0=x^2+8x+16 ?

The solutions to the equation 0=x^2+8x+16 are x=-4

Find the zeros of 0=x^2+8x+16

The zeros of 0=x^2+8x+16 are x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} + 8 x + 16

x = - 4

Solution steps

0 = x^{2} + 8 x + 16

Switch sides

x^{2} + 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

x = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

x + 3 = 0

m - 4 > 12

2^{5}

- lo g_{10} (0.01)

\frac{82}{- 41}

What are the solutions to the equation 0=x^2+8x+16 ?
The solutions to the equation 0=x^2+8x+16 are x=-4
Find the zeros of 0=x^2+8x+16
The zeros of 0=x^2+8x+16 are x=-4