What is factor 6(2p+q)^2-5(2p+q)-25 ?

The solution to factor 6(2p+q)^2-5(2p+q)-25 is (3(2p+q)+5)(2(2p+q)-5)

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factor 6(2p+q)^2-5(2p+q)-25

factor

6 (2 p + q)^{2} - 5 (2 p + q) - 25

(3 (2 p + q) + 5) (2 (2 p + q) - 5)

Solution steps

6 (2 p + q)^{2} - 5 (2 p + q) - 25

Break the expression into groups

= (6 (2 p + q)^{2} + 10 (2 p + q)) + (- 15 (2 p + q) - 25)

Factor out

2 (2 p + q)

from

6 (2 p + q)^{2} + 10 (2 p + q) : 2 (2 p + q) (3 (2 p + q) + 5)

Factor out

- 5

from

- 15 (2 p + q) - 25 : - 5 (3 (2 p + q) + 5)

= 2 (2 p + q) (3 (2 p + q) + 5) - 5 (3 (2 p + q) + 5)

Factor out common term

3 (2 p + q) + 5

= (3 (2 p + q) + 5) (2 (2 p + q) - 5)

6 t^{2} - 8 + 40 cos (π t)

(m - n)^{2} + 5 (m - n) - 24

12 (a - b)^{2} + 7 (a - b) - 12

\infty^{2} - \infty

+ 9 + x y - x - 9 y^{2}

What is factor 6(2p+q)^2-5(2p+q)-25 ?
The solution to factor 6(2p+q)^2-5(2p+q)-25 is (3(2p+q)+5)(2(2p+q)-5)