What is factor (y+z)^3+8 ?

The solution to factor (y+z)^3+8 is (y+z+2)((y+z)^2-2(y+z)+4)

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factor (y+z)^3+8

factor

(y + z)^{3} + 8

(y + z + 2) ((y + z)^{2} - 2 (y + z) + 4)

Solution steps

(y + z)^{3} + 8

Rewrite

8

2^{3}

= (y + z)^{3} + 2^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(y + z)^{3} + 2^{3} = ((y + z) + 2) ((y + z)^{2} - 2 (y + z) + 2^{2})

= ((y + z) + 2) ((y + z)^{2} - 2 (y + z) + 2^{2})

Refine

= (y + z + 2) ((y + z)^{2} - 2 (y + z) + 4)

\frac{3 z + 2}{2 z - 7} \leq 0

\frac{2}{1 + i} - \frac{3}{1 - i}

64 x^{2} + 144 x + 81

- 40 = - 5 p

(\frac{3}{2} t^{\frac{1}{2}})^{2}

What is factor (y+z)^3+8 ?
The solution to factor (y+z)^3+8 is (y+z+2)((y+z)^2-2(y+z)+4)