What is factor 1-128x^7y^7 ?

The solution to factor 1-128x^7y^7 is -(2xy-1)(64x^6y^6+32x^5y^5+16x^4y^4+8x^3y^3+4x^2y^2+2xy+1)

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factor 1-128x^7y^7

factor

1 - 128 x^{7} y^{7}

- (2 x y - 1) (64 x^{6} y^{6} + 32 x^{5} y^{5} + 16 x^{4} y^{4} + 8 x^{3} y^{3} + 4 x^{2} y^{2} + 2 x y + 1)

Solution steps

1 - 128 x^{7} y^{7}

Rewrite

128 x^{7} y^{7}

(2 x y)^{7}

= 1 - (2 x y)^{7}

Factor out common term

- 1

= - ((2 x y)^{7} - 1)

Factor

(2 x y)^{7} - 1 : (2 x y - 1) ((2 x y)^{6} + (2 x y)^{5} + (2 x y)^{4} + (2 x y)^{3} + (2 x y)^{2} + 2 x y + 1)

= - (2 x y - 1) ((2 x y)^{6} + (2 x y)^{5} + (2 x y)^{4} + (2 x y)^{3} + (2 x y)^{2} + 2 x y + 1)

Simplify

- (2 x y - 1) ((2 x y)^{6} + (2 x y)^{5} + (2 x y)^{4} + (2 x y)^{3} + (2 x y)^{2} + 2 x y + 1) : - (2 x y - 1) (64 x^{6} y^{6} + 32 x^{5} y^{5} + 16 x^{4} y^{4} + 8 x^{3} y^{3} + 4 x^{2} y^{2} + 2 x y + 1)

= - (2 x y - 1) (64 x^{6} y^{6} + 32 x^{5} y^{5} + 16 x^{4} y^{4} + 8 x^{3} y^{3} + 4 x^{2} y^{2} + 2 x y + 1)

[1.3]

\frac{x ^{3} + y ^{3}}{x + y}

a x + a y + a z + x + y + z

x + 2 2 x y + 2 y

What is factor 1-128x^7y^7 ?
The solution to factor 1-128x^7y^7 is -(2xy-1)(64x^6y^6+32x^5y^5+16x^4y^4+8x^3y^3+4x^2y^2+2xy+1)