What is the first d/(dy)((x)(2xy)) ?

The first d/(dy)((x)(2xy)) is 2x^2

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d/(dy)((x)(2xy))

\frac{d}{d y} ((x) (2 x y))

2 x^{2}

Solution steps

\frac{d}{d y} ((x) (2 x y))

Simplify

(x) (2 x y) : 2 x^{2} y

= \frac{d}{d y} (2 x^{2} y)

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x^{2} \frac{d y}{d y}

Apply the common derivative:

\frac{d y}{d y} = 1

= 2 x^{2} \cdot 1

Simplify

= 2 x^{2}

(x + 5) - (3 x^{2})

f (2 a)

1 - 4 h + 3

2 (a)^{2}

(- 2) e^{3}