What is the derivative of-2x^2y+y^2 ?

The derivative of-2x^2y+y^2 is -2(2xy+(dy)/(dx)x^2)+2y(dy)/(dx)

What is the first derivative of-2x^2y+y^2 ?

The first derivative of-2x^2y+y^2 is -2(2xy+(dy)/(dx)x^2)+2y(dy)/(dx)

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\frac{d}{d x} (- 2 x^{2} y + y^{2})

- 2 (2 x y + \frac{d y}{d x} x^{2}) + 2 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (- 2 x^{2} y + y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2} y) + \frac{d}{d x} (y^{2})

\frac{d}{d x} (2 x^{2} y) = 2 (2 x y + \frac{d y}{d x} x^{2})

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

= - 2 (2 x y + \frac{d y}{d x} x^{2}) + 2 y \frac{d y}{d x}

C (20.5)

A (2.1)

12 x^{2} y - 3 x + 4 x - 1

1 + 3 (cos (3 x))^{2}

4 x - 4 x

What is the derivative of-2x^2y+y^2 ?
The derivative of-2x^2y+y^2 is -2(2xy+(dy)/(dx)x^2)+2y(dy)/(dx)
What is the first derivative of-2x^2y+y^2 ?
The first derivative of-2x^2y+y^2 is -2(2xy+(dy)/(dx)x^2)+2y(dy)/(dx)