What are the solutions to the equation 6+5x-3x^2=7 ?

The solutions to the equation 6+5x-3x^2=7 are x=(5-sqrt(13))/6 ,x=(5+sqrt(13))/6

Find the zeros of 6+5x-3x^2=7

The zeros of 6+5x-3x^2=7 are x=(5-sqrt(13))/6 ,x=(5+sqrt(13))/6

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6 + 5 x - 3 x^{2} = 7

x = \frac{5 - 13}{6}, x = \frac{5 + 13}{6}

Decimal Notation

x = 0.23240 \dots, x = 1.43425 \dots

Solution steps

6 + 5 x - 3 x^{2} = 7

Move

7

to the left side

- 3 x^{2} + 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 3 ) ( - 1 )}{2 ( - 3 )}

5^{2} - 4 (- 3) (- 1) = 13

x_{1, 2} = \frac{- 5 \pm 13}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 5 + 13}{2 ( - 3 )}, x_{2} = \frac{- 5 - 13}{2 ( - 3 )}

x = \frac{- 5 + 13}{2 ( - 3 )} : \frac{5 - 13}{6}

x = \frac{- 5 - 13}{2 ( - 3 )} : \frac{5 + 13}{6}

The solutions to the quadratic equation are:

x = \frac{5 - 13}{6}, x = \frac{5 + 13}{6}

∣ d + 4 ∣ => 3

2 (x - 4) + 5 x = 34

2 \cdot 1 0^{- 3}

8 \cdot 2^{2}

2 x^{2} + x - 10

What are the solutions to the equation 6+5x-3x^2=7 ?
The solutions to the equation 6+5x-3x^2=7 are x=(5-sqrt(13))/6 ,x=(5+sqrt(13))/6
Find the zeros of 6+5x-3x^2=7
The zeros of 6+5x-3x^2=7 are x=(5-sqrt(13))/6 ,x=(5+sqrt(13))/6