What is the d/(dt)((x)(sin(kt))) ?

The d/(dt)((x)(sin(kt))) is (dx)/(dt)sin(kt)+cos(kt)kx(t)

What is the first d/(dt)((x)(sin(kt))) ?

The first d/(dt)((x)(sin(kt))) is (dx)/(dt)sin(kt)+cos(kt)kx(t)

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\frac{d}{d t} ((x) (sin (k t)))

\frac{d x}{d t} sin (k t) + cos (k t) k x (t)

Solution steps

\frac{d}{d t} ((x) (sin (k t)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = sin (k t)

= \frac{d x}{d t} sin (k t) + \frac{d}{d t} (sin (k t)) x

\frac{d}{d t} (sin (k t)) = cos (k t) k

= \frac{d x}{d t} sin (k t) + cos (k t) k x (t)

sin^{2} (x) - 2 sin (x) + 1

x (3 cos (2 x))

- 8

r (28 π)

f (x) = x + 3

What is the d/(dt)((x)(sin(kt))) ?
The d/(dt)((x)(sin(kt))) is (dx)/(dt)sin(kt)+cos(kt)kx(t)
What is the first d/(dt)((x)(sin(kt))) ?
The first d/(dt)((x)(sin(kt))) is (dx)/(dt)sin(kt)+cos(kt)kx(t)