What is factor 1-2sin(x)+sin^2(x) ?

The solution to factor 1-2sin(x)+sin^2(x) is (sin(x)-1)^2

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factor 1-2sin(x)+sin^2(x)

factor

1 - 2 sin (x) + sin^{2} (x)

(sin (x) - 1)^{2}

Solution steps

1 - 2 sin (x) + sin^{2} (x)

Write in the standard form

a x^{2} + b x + c

= sin^{2} (x) - 2 sin (x) + 1

Rewrite

sin^{2} (x) - 2 sin (x) + 1

sin^{2} (x) - 2 sin (x) \cdot 1 + 1^{2}

= sin^{2} (x) - 2 sin (x) \cdot 1 + 1^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = sin (x), b = 1

= (sin (x) - 1)^{2}

e^{4} + e^{2}

6 x^{2} + 2 x y - 3 x z - yz

(ln (a))^{5 c}

x y + x z + w y + w z

3 x - 6

What is factor 1-2sin(x)+sin^2(x) ?
The solution to factor 1-2sin(x)+sin^2(x) is (sin(x)-1)^2