What is factor 16x^{2n}-1 ?

The solution to factor 16x^{2n}-1 is (4x^n+1)(4x^n-1)

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factor 16x^{2n}-1

factor

16 x^{2 n} - 1

(4 x^{n} + 1) (4 x^{n} - 1)

Solution steps

16 x^{2 n} - 1

Rewrite

16 x^{2 n}

(2^{2} x^{1 n})^{2}

= (2^{2} x^{1 \cdot n})^{2} - 1

Rewrite

1

1^{2}

= (2^{2} x^{1 n})^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(2^{2} x^{1 n})^{2} - 1^{2} = (2^{2} x^{1 n} + 1) (2^{2} x^{1 n} - 1)

= (2^{2} x^{1 n} + 1) (2^{2} x^{1 n} - 1)

Refine

= (4 x^{n} + 1) (4 x^{n} - 1)

2 x (a - c) + 3 y (c - a) - 4 a z + 4 cz

e^{x} + e^{- x}

\frac{d}{d x} ((x) (y))

\frac{d}{d x} ((x) (x))

(ln (x))^{n}

What is factor 16x^{2n}-1 ?
The solution to factor 16x^{2n}-1 is (4x^n+1)(4x^n-1)