What are the solutions to the equation x^2-4x-9=0 ?

The solutions to the equation x^2-4x-9=0 are x=2+sqrt(13),x=2-sqrt(13)

Find the zeros of x^2-4x-9=0

The zeros of x^2-4x-9=0 are x=2+sqrt(13),x=2-sqrt(13)

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x^{2} - 4 x - 9 = 0

x = 2 + 13, x = 2 - 13

Decimal Notation

x = 5.60555 \dots, x = - 1.60555 \dots

Solution steps

x^{2} - 4 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 9) = 213

x_{1, 2} = \frac{- ( - 4 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 13}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 13}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 13}{2 \cdot 1} : 2 + 13

x = \frac{- ( - 4 ) - 2 13}{2 \cdot 1} : 2 - 13

The solutions to the quadratic equation are:

x = 2 + 13, x = 2 - 13

\frac{1}{3}

ab + a^{2}

5 \cdot X^{0} + 3 \cdot X^{1} + 3 \cdot X^{2} = 1 \cdot X^{0} + 0 \cdot X^{1}

x^{2} - 25 > 0

\frac{1}{12} x - \frac{1}{12} = \frac{1}{8} x + \frac{1}{6} - \frac{1}{6} x

What are the solutions to the equation x^2-4x-9=0 ?
The solutions to the equation x^2-4x-9=0 are x=2+sqrt(13),x=2-sqrt(13)
Find the zeros of x^2-4x-9=0
The zeros of x^2-4x-9=0 are x=2+sqrt(13),x=2-sqrt(13)