What is the d/(dt)((x)(t^2)) ?

The d/(dt)((x)(t^2)) is (dx)/(dt)t^2+2tx

What is the first d/(dt)((x)(t^2)) ?

The first d/(dt)((x)(t^2)) is (dx)/(dt)t^2+2tx

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\frac{d}{d t} ((x) (t^{2}))

\frac{d x}{d t} t^{2} + 2 t x

Solution steps

\frac{d}{d t} ((x) (t^{2}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = t^{2}

= \frac{d x}{d t} t^{2} + \frac{d}{d t} (t^{2}) x

\frac{d}{d t} (t^{2}) = 2 t

= \frac{d x}{d t} t^{2} + 2 t x

- 3 sin (40 t + 50)

4 x + 6 p a - 8 a - 3 p x

(x^{2}) + 2

e^{x} cos (x) + e^{x} sin (x)

(\frac{d ^{2} y}{d x ^{2}})^{2}

What is the d/(dt)((x)(t^2)) ?
The d/(dt)((x)(t^2)) is (dx)/(dt)t^2+2tx
What is the first d/(dt)((x)(t^2)) ?
The first d/(dt)((x)(t^2)) is (dx)/(dt)t^2+2tx