What is factor (m-3)^3+(j-k)^3 ?

The solution to factor (m-3)^3+(j-k)^3 is (m-3+j-k)((m-3)^2-(m-3)(j-k)+(j-k)^2)

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factor (m-3)^3+(j-k)^3

factor

(m - 3)^{3} + (j - k)^{3}

(m - 3 + j - k) ((m - 3)^{2} - (m - 3) (j - k) + (j - k)^{2})

Solution steps

(m - 3)^{3} + (j - k)^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(m - 3)^{3} + (j - k)^{3} = ((m - 3) + (j - k)) ((m - 3)^{2} - (m - 3) (j - k) + (j - k)^{2})

= ((m - 3) + (j - k)) ((m - 3)^{2} - (m - 3) (j - k) + (j - k)^{2})

Refine

= (m + j - k - 3) ((j - k)^{2} - (m - 3) (j - k) + (m - 3)^{2})

x^{2} + 11 - 36

e^{2 x} \frac{d y}{d x} + e^{2 x} 2 y

5 z + (y - x)

sin (h) (4 t)

0.04 x^{2} - 0.09

What is factor (m-3)^3+(j-k)^3 ?
The solution to factor (m-3)^3+(j-k)^3 is (m-3+j-k)((m-3)^2-(m-3)(j-k)+(j-k)^2)