What are the solutions to the equation n-n=(n(n-3))/2 ?

The solutions to the equation n-n=(n(n-3))/2 are n=3,n=0

Find the zeros of n-n=(n(n-3))/2

The zeros of n-n=(n(n-3))/2 are n=3,n=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n - n = \frac{n ( n - 3 )}{2}

n = 3, n = 0

Solution steps

n - n = \frac{n ( n - 3 )}{2}

Multiply both sides by

2

2 n - 2 n = n (n - 3)

0 = n (n - 3)

Expand

n (n - 3) : n^{2} - 3 n

0 = n^{2} - 3 n

Switch sides

n^{2} - 3 n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

n_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, n_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

n = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

n = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

n = 3, n = 0

6 - \frac{2}{3} (- 3)

\frac{5}{1 + 3 i}

2 < x + 8 < 6

\frac{1 0 ^{0} r ^{- 11} s}{3 ^{2}}

\frac{6 + 11}{5 + 3}

What are the solutions to the equation n-n=(n(n-3))/2 ?
The solutions to the equation n-n=(n(n-3))/2 are n=3,n=0
Find the zeros of n-n=(n(n-3))/2
The zeros of n-n=(n(n-3))/2 are n=3,n=0