What is factor 7(a+b)^2+8(a+b)+1 ?

The solution to factor 7(a+b)^2+8(a+b)+1 is (7(a+b)+1)(a+b+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 7(a+b)^2+8(a+b)+1

factor

7 (a + b)^{2} + 8 (a + b) + 1

(7 (a + b) + 1) (a + b + 1)

Solution steps

7 (a + b)^{2} + 8 (a + b) + 1

Break the expression into groups

= (7 (a + b)^{2} + (a + b)) + (7 (a + b) + 1)

Factor out

(a + b)

from

7 (a + b)^{2} + (a + b) : (a + b) (7 (a + b) + 1)

= (a + b) (7 (a + b) + 1) + (7 (a + b) + 1)

Factor out common term

7 (a + b) + 1

= (7 (a + b) + 1) ((a + b) + 1)

Refine

= (a + b + 1) (7 (a + b) + 1)

\frac{6 + 2 2}{7}

(cos (x))^{2} + 1

(4 a + b) + (2 x - y)

\frac{5 a - 5}{8 a - 8}

(a - b)^{2} + 9 + 6 (a - b)

What is factor 7(a+b)^2+8(a+b)+1 ?
The solution to factor 7(a+b)^2+8(a+b)+1 is (7(a+b)+1)(a+b+1)