What is factor a^4m+a^4n-b^4m-b^4n ?

The solution to factor a^4m+a^4n-b^4m-b^4n is (m+n)(a^2+b^2)(a+b)(a-b)

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factor a^4m+a^4n-b^4m-b^4n

factor

a^{4} m + a^{4} n - b^{4} m - b^{4} n

(m + n) (a^{2} + b^{2}) (a + b) (a - b)

Solution steps

a^{4} m + a^{4} n - b^{4} m - b^{4} n

Factor out common term

a^{4}

= a^{4} (m + n) - b^{4} m - b^{4} n

Factor out common term

b^{4}

= a^{4} (m + n) - b^{4} (m + n)

Factor out common term

(m + n)

= (m + n) (a^{4} - b^{4})

Factor

- b^{4} + a^{4} : (a^{2} + b^{2}) (a + b) (a - b)

= (m + n) (b + a) (- b + a) (b^{2} + a^{2})

3 sin^{2} (x) - 4 sin (x) - 4

x^{2 - 9}

x^{2} + 4 k x + (3 + 11 k)

e^{12} - e^{6}

27 - (m + 2 n)^{3}

What is factor a^4m+a^4n-b^4m-b^4n ?
The solution to factor a^4m+a^4n-b^4m-b^4n is (m+n)(a^2+b^2)(a+b)(a-b)