What is factor 1-x+0.25x^2 ?

The solution to factor 1-x+0.25x^2 is (0.5x-1)^2

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factor 1-x+0.25x^2

factor

1 - x + 0.25 x^{2}

(0.5 x - 1)^{2}

Solution steps

1 - x + 0.25 x^{2}

Write in the standard form

a x^{2} + b x + c

= 0.25 x^{2} - x + 1

Rewrite

0.25 x^{2} - x + 1

(0.25 x)^{2} - 2 \cdot 0.5 x \cdot 1 + 1^{2}

= (0.25 x)^{2} - 2 \cdot 0.5 x \cdot 1 + 1^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = 0.5 x, b = 1

= (0.5 x - 1)^{2}

- (+ 9)

6 sin^{2} (x) - 5 sin (x) - 25

7^{26} (- 7)^{25}

(x - 3) - (2 x^{2})

[- 6.9]