What is factor (x+1)(x+3)(x-5)(x-7)+28 ?

The solution to factor (x+1)(x+3)(x-5)(x-7)+28 is x^4-8x^3-10x^2+104x+133

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factor (x+1)(x+3)(x-5)(x-7)+28

factor

(x + 1) (x + 3) (x - 5) (x - 7) + 28

x^{4} - 8 x^{3} - 10 x^{2} + 104 x + 133

Solution steps

(x + 1) (x + 3) (x - 5) (x - 7) + 28

Expand

(x + 1) (x + 3) (x - 5) (x - 7) : x^{4} - 8 x^{3} - 10 x^{2} + 104 x + 105

= x^{4} - 8 x^{3} - 10 x^{2} + 104 x + 105 + 28

Add the numbers:

105 + 28 = 133

= x^{4} - 8 x^{3} - 10 x^{2} + 104 x + 133

5 (x - 6) - 10 (x - 6) + 12 (x - 6)

\frac{( x - 2 ) ^{2} - 4}{x}

3 (a)^{2}

[x + (- 2)] [x + (- 1)]

+ (- 15)

What is factor (x+1)(x+3)(x-5)(x-7)+28 ?
The solution to factor (x+1)(x+3)(x-5)(x-7)+28 is x^4-8x^3-10x^2+104x+133