What are the solutions to the equation 5x^2-14x+6=-x ?

The solutions to the equation 5x^2-14x+6=-x are x=2,x= 3/5

Find the zeros of 5x^2-14x+6=-x

The zeros of 5x^2-14x+6=-x are x=2,x= 3/5

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5 x^{2} - 14 x + 6 = - x

x = 2, x = \frac{3}{5}

Solution steps

5 x^{2} - 14 x + 6 = - x

Move

x

to the left side

5 x^{2} - 13 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

(- 13)^{2} - 4 \cdot 5 \cdot 6 = 7

x_{1, 2} = \frac{- ( - 13 ) \pm 7}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 7}{2 \cdot 5}, x_{2} = \frac{- ( - 13 ) - 7}{2 \cdot 5}

x = \frac{- ( - 13 ) + 7}{2 \cdot 5} : 2

x = \frac{- ( - 13 ) - 7}{2 \cdot 5} : \frac{3}{5}

The solutions to the quadratic equation are:

x = 2, x = \frac{3}{5}

x^{2} (x + 6) + 12 (x + 1) \geq 4

5 w < 55

1 + 2 b - 4 = - 3

x^{2} + 2 x = - 10

12 \leq 4 n < 28

What are the solutions to the equation 5x^2-14x+6=-x ?
The solutions to the equation 5x^2-14x+6=-x are x=2,x= 3/5
Find the zeros of 5x^2-14x+6=-x
The zeros of 5x^2-14x+6=-x are x=2,x= 3/5