What is factor (x-5)+(4x^2) ?

The solution to factor (x-5)+(4x^2) is (x-1)(4x+5)

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factor (x-5)+(4x^2)

factor

(x - 5) + (4 x^{2})

(x - 1) (4 x + 5)

Solution steps

(x - 5) + (4 x^{2})

Remove parentheses:

(a) = a

= x - 5 + 4 x^{2}

Write in the standard form

a x^{2} + b x + c

= 4 x^{2} + x - 5

Break the expression into groups

= (4 x^{2} - 4 x) + (5 x - 5)

Factor out

4 x

from

4 x^{2} - 4 x : 4 x (x - 1)

Factor out

5

from

5 x - 5 : 5 (x - 1)

= 4 x (x - 1) + 5 (x - 1)

Factor out common term

x - 1

= (x - 1) (4 x + 5)

9 b^{2 x} - \frac{1}{4}

e^{2 + 2 i}

2 m x - 20 n y - 8 n x + 5 m y

[(x + 8) - y]^{2}

x (a + b - c) - (- y (a + b - c))

What is factor (x-5)+(4x^2) ?
The solution to factor (x-5)+(4x^2) is (x-1)(4x+5)