What is factor (pk)^2+5pk-14 ?

The solution to factor (pk)^2+5pk-14 is (pk-2)(pk+7)

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factor (pk)^2+5pk-14

factor

(p k)^{2} + 5 p k - 14

(p k - 2) (p k + 7)

Solution steps

(p k)^{2} + 5 p k - 14

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= p^{2} k^{2} + 5 p k - 14

Break the expression into groups

= (p^{2} k^{2} - 2 p k) + (7 p k - 14)

Factor out

p k

from

p^{2} k^{2} - 2 p k : p k (p k - 2)

Factor out

7

from

7 p k - 14 : 7 (p k - 2)

= p k (p k - 2) + 7 (p k - 2)

Factor out common term

p k - 2

= (p k - 2) (p k + 7)

x^{3 + 1}

a e^{ik x} + b e^{- ik x}

[- 2.11]

(sin (x))^{2} + 1

4 x^{2} + 15 x + (- 16)

What is factor (pk)^2+5pk-14 ?
The solution to factor (pk)^2+5pk-14 is (pk-2)(pk+7)