What is factor 243x^5+1 ?

The solution to factor 243x^5+1 is (3x+1)(81x^4-27x^3+9x^2-3x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 243x^5+1

factor

243 x^{5} + 1

(3 x + 1) (81 x^{4} - 27 x^{3} + 9 x^{2} - 3 x + 1)

Solution steps

243 x^{5} + 1

Apply exponent rules

= (3 x)^{5} + 1^{5}

Apply factoring rule:

x^{n} + y^{n} = (x + y) (x^{n - 1} - x^{n - 2} y + \dots - x y^{n - 2} + y^{n - 1}), n i s o dd

(3 x)^{5} + 1^{5} = (3 x + 1) (3^{4} x^{4} - 3^{3} x^{3} + 3^{2} x^{2} - 3 x + 1)

= (3 x + 1) (3^{4} x^{4} - 3^{3} x^{3} + 3^{2} x^{2} - 3 x + 1)

Simplify

(3 x + 1) (3^{4} x^{4} - 3^{3} x^{3} + 3^{2} x^{2} - 3 x + 1) : (3 x + 1) (81 x^{4} - 27 x^{3} + 9 x^{2} - 3 x + 1)

= (3 x + 1) (81 x^{4} - 27 x^{3} + 9 x^{2} - 3 x + 1)

x^{2} - 6 x = 14

\frac{64}{16}

x^{2} - 210 x = 0

\frac{2}{4 - 5 i}

(7 x^{4})^{2}

What is factor 243x^5+1 ?
The solution to factor 243x^5+1 is (3x+1)(81x^4-27x^3+9x^2-3x+1)