What is factor b^2+7b-18 ?

The solution to factor b^2+7b-18 is (b-2)(b+9)

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factor b^2+7b-18

factor

b^{2} + 7 b - 18

(b - 2) (b + 9)

Solution steps

b^{2} + 7 b - 18

Break the expression into groups

= (b^{2} - 2 b) + (9 b - 18)

Factor out

b

from

b^{2} - 2 b : b (b - 2)

Factor out

9

from

9 b - 18 : 9 (b - 2)

= b (b - 2) + 9 (b - 2)

Factor out common term

b - 2

= (b - 2) (b + 9)

- 3 (x - 2) (x + 3)^{2} (x - 11) > 0

9 ∣ 3 n - 2 ∣ + 6 > 51

\frac{x + 5}{3} - \frac{1}{2} x + 3 (2 x - \frac{1}{2}) = 5 (\frac{x}{2} - 2)

24 \cdot 7

(\frac{y}{6})^{2}