What is the d/(dt)((x)(t^3)) ?

The d/(dt)((x)(t^3)) is (dx)/(dt)t^3+3t^2x

What is the first d/(dt)((x)(t^3)) ?

The first d/(dt)((x)(t^3)) is (dx)/(dt)t^3+3t^2x

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\frac{d}{d t} ((x) (t^{3}))

\frac{d x}{d t} t^{3} + 3 t^{2} x

Solution steps

\frac{d}{d t} ((x) (t^{3}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = t^{3}

= \frac{d x}{d t} t^{3} + \frac{d}{d t} (t^{3}) x

\frac{d}{d t} (t^{3}) = 3 t^{2}

= \frac{d x}{d t} t^{3} + 3 t^{2} x

2 \cdot 3^{i} - 4 \cdot i

3 x - 2 - (2 x^{3})

a^{0.4} + (- 7)

x^{(2)} + x + 1

x z + x w + yz + y w

What is the d/(dt)((x)(t^3)) ?
The d/(dt)((x)(t^3)) is (dx)/(dt)t^3+3t^2x
What is the first d/(dt)((x)(t^3)) ?
The first d/(dt)((x)(t^3)) is (dx)/(dt)t^3+3t^2x