What is factor 6xc+yd+2dx+3cy ?

The solution to factor 6xc+yd+2dx+3cy is (d+3c)(2x+y)

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factor 6xc+yd+2dx+3cy

factor

6 x c + y d + 2 d x + 3 cy

(d + 3 c) (2 x + y)

Solution steps

6 x c + y d + 2 d x + 3 cy

Rewrite as

= 3 \cdot 2 x c + y d + 2 x d + 3 cy

Factor out common term

2 x

= 2 x (3 c + d) + y d + 3 cy

Factor out common term

y

= 2 x (d + 3 c) + y (d + 3 c)

Factor out common term

(d + 3 c)

= (d + 3 c) (2 x + y)

(sec (t))^{2}

\frac{x ^{6} - 1}{x ^{3} - 1}

cos (2 θ - 90)

(\frac{d}{d x} (- x))^{m}

x^{2} + 3^{2}

What is factor 6xc+yd+2dx+3cy ?
The solution to factor 6xc+yd+2dx+3cy is (d+3c)(2x+y)