What is factor 64(o+p)^3-q^3 ?

The solution to factor 64(o+p)^3-q^3 is (4(o+p)-q)(16(o+p)^2+4q(o+p)+q^2)

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factor 64(o+p)^3-q^3

factor

64 (o + p)^{3} - q^{3}

(4 (o + p) - q) (16 (o + p)^{2} + 4 q (o + p) + q^{2})

Solution steps

64 (o + p)^{3} - q^{3}

Rewrite

64 (o + p)^{3} - q^{3}

(4 (o + p))^{3} - q^{3}

= (4 (o + p))^{3} - q^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(4 (o + p))^{3} - q^{3} = (4 (o + p) - q) (4^{2} (o + p)^{2} + 4 (o + p) q + q^{2})

= (4 (o + p) - q) (4^{2} (o + p)^{2} + 4 q (o + p) + q^{2})

Refine

= (4 (o + p) - q) (16 (o + p)^{2} + 4 q (o + p) + q^{2})

\frac{d}{d t} ((x (t, C)) (C e^{t}))

d^{3} e^{6} f^{9} - 216

+ a^{2} - x y + a x - a y

4 e^{2} + 7 e^{3} + 9 e^{4}

\frac{x ^{2} - 3 x}{x}

What is factor 64(o+p)^3-q^3 ?
The solution to factor 64(o+p)^3-q^3 is (4(o+p)-q)(16(o+p)^2+4q(o+p)+q^2)