What are the solutions to the equation 6x^2-4=5x ?

The solutions to the equation 6x^2-4=5x are x= 4/3 ,x=-1/2

Find the zeros of 6x^2-4=5x

The zeros of 6x^2-4=5x are x= 4/3 ,x=-1/2

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6 x^{2} - 4 = 5 x

x = \frac{4}{3}, x = - \frac{1}{2}

Decimal Notation

x = 1.33333 \dots, x = - 0.5

Solution steps

6 x^{2} - 4 = 5 x

Move

5 x

to the left side

6 x^{2} - 4 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 ( - 4 )}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 (- 4) = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 6}, x_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 6}

x = \frac{- ( - 5 ) + 11}{2 \cdot 6} : \frac{4}{3}

x = \frac{- ( - 5 ) - 11}{2 \cdot 6} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - \frac{1}{2}

81 x^{4} - 625

\frac{y}{5} = 6

2 \cdot 36

7 x - \frac{3}{8} = 6 x - \frac{5}{8}

6 x = 8

What are the solutions to the equation 6x^2-4=5x ?
The solutions to the equation 6x^2-4=5x are x= 4/3 ,x=-1/2
Find the zeros of 6x^2-4=5x
The zeros of 6x^2-4=5x are x= 4/3 ,x=-1/2