What is the d/(dt)((w)(sin(wt))) ?

The d/(dt)((w)(sin(wt))) is w^2cos(wt)

What is the first d/(dt)((w)(sin(wt))) ?

The first d/(dt)((w)(sin(wt))) is w^2cos(wt)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} ((w) (sin (wt)))

w^{2} cos (wt)

Solution steps

\frac{d}{d t} ((w) (sin (wt)))

Treat

w

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= w \frac{d}{d t} (sin (wt))

Apply the chain rule:

cos (wt) \frac{d}{d t} (wt)

= cos (wt) \frac{d}{d t} (wt)

\frac{d}{d t} (wt) = w

= w cos (wt) w

Simplify

w cos (wt) w : w^{2} cos (wt)

= w^{2} cos (wt)

12 + 3 y - 4 x - x y + 8 y + 2 y^{2}

2 7^{2} - 2 6^{2}

x 2 + 4 x + 5

x^{2} - (2 x - 1)^{2} - 6 x + 9

2 x^{2} - 8 x

What is the d/(dt)((w)(sin(wt))) ?
The d/(dt)((w)(sin(wt))) is w^2cos(wt)
What is the first d/(dt)((w)(sin(wt))) ?
The first d/(dt)((w)(sin(wt))) is w^2cos(wt)