What is factor 1+2tan(x)+tan^2(x) ?

The solution to factor 1+2tan(x)+tan^2(x) is (tan(x)+1)^2

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factor 1+2tan(x)+tan^2(x)

factor

1 + 2 tan (x) + tan^{2} (x)

(tan (x) + 1)^{2}

Solution steps

1 + 2 tan (x) + tan^{2} (x)

Write in the standard form

a x^{2} + b x + c

= tan^{2} (x) + 2 tan (x) + 1

Rewrite

tan^{2} (x) + 2 tan (x) + 1

tan^{2} (x) + 2 tan (x) \cdot 1 + 1^{2}

= tan^{2} (x) + 2 tan (x) \cdot 1 + 1^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = tan (x), b = 1

= (tan (x) + 1)^{2}

\frac{x ^{2} - 5 x + 6}{x - 5}

Q (x) + \frac{d}{d x} ((Q (x)) (d x))

6 y^{5} - 198 y

m^{2} + mm + m x + n x

2 x^{a^{(b - 4)}}

What is factor 1+2tan(x)+tan^2(x) ?
The solution to factor 1+2tan(x)+tan^2(x) is (tan(x)+1)^2