What is factor 8(z^2-9z-7)'+(z^2-9) ?

The solution to factor 8(z^2-9z-7)'+(z^2-9) is 8(z^2-9z-7)'+z^2-9

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factor 8(z^2-9z-7)'+(z^2-9)

factor

8 (z^{2} - 9 z - 7)^{'} + (z^{2} - 9)

8 (z^{2} - 9 z - 7)' + z^{2} - 9

Solution steps

8 (z^{2} - 9 z - 7)^{'} + (z^{2} - 9)

Remove parentheses:

(a) = a

= 8 (z^{2} - 9 z - 7)^{^{'}} + z^{2} - 9

9 a x - 3 b x + 21 a y - 7 b y

12 5^{3} + 1

4 x + (- 5)

(2 x + 1)^{3} - 8

x^{3} + 2 x - 5 x - 6

What is factor 8(z^2-9z-7)'+(z^2-9) ?
The solution to factor 8(z^2-9z-7)'+(z^2-9) is 8(z^2-9z-7)'+z^2-9