What is factor 2ac^2+bc^2-2ac-bc-2a-b ?

The solution to factor 2ac^2+bc^2-2ac-bc-2a-b is (-1+c(-1+c))(2a+b)

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factor 2ac^2+bc^2-2ac-bc-2a-b

factor

2 a c^{2} + b c^{2} - 2 a c - b c - 2 a - b

(- 1 + c (- 1 + c)) (2 a + b)

Solution steps

2 a c^{2} + b c^{2} - 2 a c - b c - 2 a - b

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

c^{2} = cc

= 2 a cc + b cc - 2 a c - b c - 2 a - b

Rewrite as

= 2 c a c + b c^{2} - 1 \cdot 2 c a - b c - 2 a - b

Factor out common term

2 c a

= 2 c a (c - 1) + b c^{2} - b c - 2 a - b

Rewrite as

= 2 a c (- 1 + c) + b c^{2} - b c - 1 \cdot 2 a - b

Factor out common term

2 a

= 2 a (c (- 1 + c) - 1) + b c^{2} - b c - b

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

c^{2} = cc

= 2 a (- 1 + (- 1 + c) c) + b cc - b c - b

Factor out common term

c b

= 2 a (- 1 + (- 1 + c) c) + c b (c - 1) - b

Factor out common term

b

= 2 a (- 1 + (- 1 + c) c) + b (c (- 1 + c) - 1)

Factor out common term

(- 1 + (- 1 + c) c)

= (- 1 + (- 1 + c) c) (2 a + b)

v (- 1.2)

\frac{1}{2} (ln (2))

[(x - y) + z] [(x - y) - z]

x^{2} + x y - b x - b y

(cos (2 t))^{3}

What is factor 2ac^2+bc^2-2ac-bc-2a-b ?
The solution to factor 2ac^2+bc^2-2ac-bc-2a-b is (-1+c(-1+c))(2a+b)