What are the solutions to the equation -7x^2+x+9=-6x ?

The solutions to the equation -7x^2+x+9=-6x are x=-(-7+sqrt(301))/(14),x=(7+sqrt(301))/(14)

Find the zeros of -7x^2+x+9=-6x

The zeros of -7x^2+x+9=-6x are x=-(-7+sqrt(301))/(14),x=(7+sqrt(301))/(14)

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- 7 x^{2} + x + 9 = - 6 x

x = - \frac{- 7 + 301}{14}, x = \frac{7 + 301}{14}

Solution steps

- 7 x^{2} + x + 9 = - 6 x

Move

6 x

to the left side

- 7 x^{2} + 7 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 7 ) \cdot 9}{2 ( - 7 )}

7^{2} - 4 (- 7) \cdot 9 = 301

x_{1, 2} = \frac{- 7 \pm 301}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 7 + 301}{2 ( - 7 )}, x_{2} = \frac{- 7 - 301}{2 ( - 7 )}

x = \frac{- 7 + 301}{2 ( - 7 )} : - \frac{- 7 + 301}{14}

x = \frac{- 7 - 301}{2 ( - 7 )} : \frac{7 + 301}{14}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 301}{14}, x = \frac{7 + 301}{14}

x^{2} + 16 < 0

- 0.1 + 11 < 18 x + 31 - 11 + 11 < 0.1 + 11

∣ 7 x + 5 ∣ = ∣ 3 x - 13 ∣

g (5) = (2 \cdot 5) + 3

π x^{2} - π y^{2} + π z^{2}

What are the solutions to the equation -7x^2+x+9=-6x ?
The solutions to the equation -7x^2+x+9=-6x are x=-(-7+sqrt(301))/(14),x=(7+sqrt(301))/(14)
Find the zeros of -7x^2+x+9=-6x
The zeros of -7x^2+x+9=-6x are x=-(-7+sqrt(301))/(14),x=(7+sqrt(301))/(14)