What is factor (x^2)+(4x-5) ?

The solution to factor (x^2)+(4x-5) is (x-1)(x+5)

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factor (x^2)+(4x-5)

factor

(x^{2}) + (4 x - 5)

(x - 1) (x + 5)

Solution steps

(x^{2}) + (4 x - 5)

Remove parentheses:

(a) = a

= x^{2} + 4 x - 5

Break the expression into groups

= (x^{2} - x) + (5 x - 5)

Factor out

x

from

x^{2} - x : x (x - 1)

Factor out

5

from

5 x - 5 : 5 (x - 1)

= x (x - 1) + 5 (x - 1)

Factor out common term

x - 1

= (x - 1) (x + 5)

a c + a d - b c - b d

n (A U B)

27 x^{3} y^{6} + z^{9}

4 a - 3 a c + 8 b - 6 b c

\frac{1}{1 + e ^{10}}