What is the d/(dθ)(({r}(θ))(θ^2)) ?

The d/(dθ)(({r}(θ))(θ^2)) is d/(dθ)({r}(θ))θ^2+2θ{r}(θ)

What is the first d/(dθ)(({r}(θ))(θ^2)) ?

The first d/(dθ)(({r}(θ))(θ^2)) is d/(dθ)({r}(θ))θ^2+2θ{r}(θ)

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\frac{d}{d θ} ((r (θ)) (θ^{2}))

\frac{d}{d θ} (r (θ)) θ^{2} + 2 θ r (θ)

Solution steps

\frac{d}{d θ} ((r (θ)) (θ^{2}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = r (θ), g = θ^{2}

= \frac{d}{d θ} (r (θ)) θ^{2} + \frac{d}{d θ} (θ^{2}) r (θ)

\frac{d}{d θ} (θ^{2}) = 2 θ

= \frac{d}{d θ} (r (θ)) θ^{2} + 2 θ r (θ)

10 x - 10 y + x m - y m

d x [sin (x^{(3)} + 2) + tan (8 x)]

- 7 x + (- 2 y)

(4 x y) - 1

(- 8 - 6 i)

What is the d/(dθ)(({r}(θ))(θ^2)) ?
The d/(dθ)(({r}(θ))(θ^2)) is d/(dθ)({r}(θ))θ^2+2θ{r}(θ)
What is the first d/(dθ)(({r}(θ))(θ^2)) ?
The first d/(dθ)(({r}(θ))(θ^2)) is d/(dθ)({r}(θ))θ^2+2θ{r}(θ)