What is factor b^2+b-20 ?

The solution to factor b^2+b-20 is (b-4)(b+5)

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factor b^2+b-20

factor

b^{2} + b - 20

(b - 4) (b + 5)

Solution steps

b^{2} + b - 20

Break the expression into groups

= (b^{2} - 4 b) + (5 b - 20)

Factor out

b

from

b^{2} - 4 b : b (b - 4)

Factor out

5

from

5 b - 20 : 5 (b - 4)

= b (b - 4) + 5 (b - 4)

Factor out common term

b - 4

= (b - 4) (b + 5)

8^{3} = 16

x^{4} + 20 x^{2} + 100

- \frac{1}{0.02}

(- 4)^{\frac{2}{7}}

\frac{7}{6}