What are the solutions to the equation 61-61x=(8x+3)(x-1) ?

The solutions to the equation 61-61x=(8x+3)(x-1) are x=1,x=-8

Find the zeros of 61-61x=(8x+3)(x-1)

The zeros of 61-61x=(8x+3)(x-1) are x=1,x=-8

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61 - 61 x = (8 x + 3) (x - 1)

x = 1, x = - 8

Solution steps

61 - 61 x = (8 x + 3) (x - 1)

Expand

(8 x + 3) (x - 1) : 8 x^{2} - 5 x - 3

61 - 61 x = 8 x^{2} - 5 x - 3

Switch sides

8 x^{2} - 5 x - 3 = 61 - 61 x

Move

61 x

to the left side

8 x^{2} + 56 x - 3 = 61

Move

61

to the left side

8 x^{2} + 56 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 56 \pm 5 6 ^{2} - 4 \cdot 8 ( - 64 )}{2 \cdot 8}

5 6^{2} - 4 \cdot 8 (- 64) = 72

x_{1, 2} = \frac{- 56 \pm 72}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 56 + 72}{2 \cdot 8}, x_{2} = \frac{- 56 - 72}{2 \cdot 8}

x = \frac{- 56 + 72}{2 \cdot 8} : 1

x = \frac{- 56 - 72}{2 \cdot 8} : - 8

The solutions to the quadratic equation are:

x = 1, x = - 8

2 x + 10 = 16

- 1 + 7 (m + 4) \leq 2 m - 4

28 x^{3} - 49 x^{2}

5^{\frac{1}{3}} \cdot 5^{\frac{3}{5}}

45 x^{7} - 5 x

What are the solutions to the equation 61-61x=(8x+3)(x-1) ?
The solutions to the equation 61-61x=(8x+3)(x-1) are x=1,x=-8
Find the zeros of 61-61x=(8x+3)(x-1)
The zeros of 61-61x=(8x+3)(x-1) are x=1,x=-8